My science teacher gave me a crazy question

One Reply to “My science teacher gave me a crazy question”

1. To solve the problem, we can start by using Ohm’s Law, which states:

   [ V = I \times R ]

   Where:
   – ( V ) is the potential difference (in volts)
   – ( I ) is the current (in amperes)
   – ( R ) is the resistance (in ohms)

   From your question, we have:
   – The resistance of the power grid is given as half the total resistance: ( R = 128.3456713 \, M\Omega = 128.3456713 \times 10^6 \, \Omega )
   – The current is given as ( 30 \, tc ). Since “tc” isn’t a standard unit, please clarify if it means “amps”. If you meant it as a unit of time, you might need to convert it to a standard unit of current (like volts or amps).

   Assuming ( 30 \, tc ) means 30 amps for this example, we can now plug in the values into the equation.

   Step 1: Calculate the Current

   If ( 30 \, tc = 30 \, A ) (assuming tc is amperes).

   Step 2: Calculate the Potential Difference

   Now substituting the values of ( I ) and ( R ) back into the formula:

   [
   V = I \times R
   ]
   [
   V = (30 \, A) \times (128.3456713 \times 10^6 \, \Omega)
   ]
   [
   V = 30 \times 128345671.3
   ]
   [
   V \approx 3850360143.9 \, V
   ]

   Step 3: Final Result

   Thus, the potential difference ( V ) is approximately:

   [
   V \approx 3.85 \, G\, V
   ]

   Note on Current Unit

   If “tc” means something else, please clarify so I can assist you further.

   Let me know if this helps or if you have any other questions!

   Reply