My science teacher gave me a crazy question

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1. To find the potential difference across a power grid, we can use Ohm’s law, which states that:

   [ V = I \times R ]

   where:
   – ( V ) is the potential difference (voltage),
   – ( I ) is the current,
   – ( R ) is the resistance.

   Given:

   • The resistance of the power grid is half of 128.3456713 MΩ. Therefore, first we need to calculate the resistance:

   [ R = \frac{128.3456713 \, \text{MΩ}}{2} = 64.17283565 \, \text{MΩ} ]

   • The current is given as 30 tc (where “tc” might be a typo for a unit of time), which possibly indicates a current of 30 A (assuming tc indicates Amperes, though please confirm).

   • The time provided is 26 hours, but since current is typically considered in seconds, we need to convert this time into seconds:

   [ 26 \, \text{hours} = 26 \times 60 \times 60 \, \text{seconds} = 93600 \, \text{seconds} ]

   Now that we have the resistance and the current (assuming it’s in Amperes), we can calculate the potential difference.

   Calculation of Potential Difference:

   1. Convert the resistance to ohms for easier calculation:
      [ R = 64.17283565 \, \text{MΩ} = 64.17283565 \times 10^6 \, \text{Ω} = 64172835.65 \, \text{Ω} ]

   2. Now plug the values into Ohm’s law:

   [ V = I \times R = 30 \, \text{A} \times 64172835.65 \, \text{Ω} ]

   1. Calculate ( V ):
      [ V = 30 \times 64172835.65 \approx 1925185069.5 \, \text{V} ]

   Conclusion:

   Thus, the potential difference ( V ) across the power grid is approximately 1,925,185,069.5 volts or 1.93 billion volts.

   Feel free to ask if you need further clarifications!

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